1/3(2x+3)^2=2

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Solution for 1/3(2x+3)^2=2 equation: 



1/3(2x+3)^2=2

We move all terms to the left:

1/3(2x+3)^2-(2)=0



Domain of the equation: 3(2x+3)^2!=0

x∈R



We multiply all the terms by the denominator


-2*3(2x+3)^2+1=0

Wy multiply elements

-6x(2+1=0

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